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530154324433 is a prime number
BaseRepresentation
bin1111011011011111010…
…10010000000111010001
31212200102100220002221101
413231233222100013101
532141224001340213
61043314411024401
753205501255556
oct7555752200721
91780370802841
10530154324433
11194923327788
12868b773b101
133acbb4971b6
141b933d60a2d
15dbcd092bdd
hex7b6fa901d1

530154324433 has 2 divisors, whose sum is σ = 530154324434. Its totient is φ = 530154324432.

The previous prime is 530154324409. The next prime is 530154324451. The reversal of 530154324433 is 334423451035.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 519333539904 + 10820784529 = 720648^2 + 104023^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-530154324433 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 530154324392 and 530154324401.

It is not a weakly prime, because it can be changed into another prime (530154327433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265077162216 + 265077162217.

It is an arithmetic number, because the mean of its divisors is an integer number (265077162217).

Almost surely, 2530154324433 is an apocalyptic number.

It is an amenable number.

530154324433 is a deficient number, since it is larger than the sum of its proper divisors (1).

530154324433 is an equidigital number, since it uses as much as digits as its factorization.

530154324433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 259200, while the sum is 37.

Adding to 530154324433 its reverse (334423451035), we get a palindrome (864577775468).

The spelling of 530154324433 in words is "five hundred thirty billion, one hundred fifty-four million, three hundred twenty-four thousand, four hundred thirty-three".