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53015502437 is a prime number
BaseRepresentation
bin110001010111111110…
…000101111001100101
312001211202000120022022
4301113332011321211
51332033432034222
640204402112525
73554526223022
oct612776057145
9161752016268
1053015502437
1120535961727
12a33694b745
134ccb7214b1
1427cd010549
1515a449c042
hexc57f85e65

53015502437 has 2 divisors, whose sum is σ = 53015502438. Its totient is φ = 53015502436.

The previous prime is 53015502367. The next prime is 53015502461. The reversal of 53015502437 is 73420551035.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 44706450721 + 8309051716 = 211439^2 + 91154^2 .

It is a cyclic number.

It is not a de Polignac number, because 53015502437 - 214 = 53015486053 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 53015502397 and 53015502406.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (53015502037) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26507751218 + 26507751219.

It is an arithmetic number, because the mean of its divisors is an integer number (26507751219).

Almost surely, 253015502437 is an apocalyptic number.

It is an amenable number.

53015502437 is a deficient number, since it is larger than the sum of its proper divisors (1).

53015502437 is an equidigital number, since it uses as much as digits as its factorization.

53015502437 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 63000, while the sum is 35.

The spelling of 53015502437 in words is "fifty-three billion, fifteen million, five hundred two thousand, four hundred thirty-seven".