Base | Representation |
---|---|
bin | 1001111000000000… |
… | …00111110110010111 |
3 | 111200110221211102211 |
4 | 10330000013312113 |
5 | 41324204214112 |
6 | 2234024214251 |
7 | 245244063151 |
oct | 47400076627 |
9 | 14613854384 |
10 | 5301632407 |
11 | 22806a6995 |
12 | 103b60a387 |
13 | 6664ab6c6 |
14 | 38417bad1 |
15 | 2106890a7 |
hex | 13c007d97 |
5301632407 has 2 divisors, whose sum is σ = 5301632408. Its totient is φ = 5301632406.
The previous prime is 5301632381. The next prime is 5301632437. The reversal of 5301632407 is 7042361035.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5301632407 - 27 = 5301632279 is a prime.
It is a super-2 number, since 2×53016324072 = 56214612357905227298, which contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5301632437) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2650816203 + 2650816204.
It is an arithmetic number, because the mean of its divisors is an integer number (2650816204).
Almost surely, 25301632407 is an apocalyptic number.
5301632407 is a deficient number, since it is larger than the sum of its proper divisors (1).
5301632407 is an equidigital number, since it uses as much as digits as its factorization.
5301632407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15120, while the sum is 31.
The square root of 5301632407 is about 72812.3094469610. The cubic root of 5301632407 is about 1743.6923843675.
The spelling of 5301632407 in words is "five billion, three hundred one million, six hundred thirty-two thousand, four hundred seven".
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