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530201036541313 is a prime number
BaseRepresentation
bin111100010001101110000110…
…0011100010100110110000001
32120112021201112211222211210001
41320203130030130110312001
51023443303210323310223
65115350554343440001
7216451521644063344
oct17043341434246601
92515251484884701
10530201036541313
11143a35aa68a6935
124b57061a456001
13199ac987ab4757
1494cdc1d42845b
154146b2bb499ad
hex1e2370c714d81

530201036541313 has 2 divisors, whose sum is σ = 530201036541314. Its totient is φ = 530201036541312.

The previous prime is 530201036541289. The next prime is 530201036541457. The reversal of 530201036541313 is 313145630102035.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 510624951328144 + 19576085213169 = 22597012^2 + 4424487^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-530201036541313 is a prime.

It is a super-2 number, since 2×5302010365413132 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (530201036571313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265100518270656 + 265100518270657.

It is an arithmetic number, because the mean of its divisors is an integer number (265100518270657).

Almost surely, 2530201036541313 is an apocalyptic number.

It is an amenable number.

530201036541313 is a deficient number, since it is larger than the sum of its proper divisors (1).

530201036541313 is an equidigital number, since it uses as much as digits as its factorization.

530201036541313 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 97200, while the sum is 37.

Adding to 530201036541313 its reverse (313145630102035), we get a palindrome (843346666643348).

The spelling of 530201036541313 in words is "five hundred thirty trillion, two hundred one billion, thirty-six million, five hundred forty-one thousand, three hundred thirteen".