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530201036541457 is a prime number
BaseRepresentation
bin111100010001101110000110…
…0011100010100111000010001
32120112021201112211222211222101
41320203130030130110320101
51023443303210323311312
65115350554343440401
7216451521644063641
oct17043341434247021
92515251484884871
10530201036541457
11143a35aa68a6a56
124b57061a456101
13199ac987ab4838
1494cdc1d428521
154146b2bb49a57
hex1e2370c714e11

530201036541457 has 2 divisors, whose sum is σ = 530201036541458. Its totient is φ = 530201036541456.

The previous prime is 530201036541313. The next prime is 530201036541467. The reversal of 530201036541457 is 754145630102035.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 433534071033361 + 96666965508096 = 20821481^2 + 9831936^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-530201036541457 is a prime.

It is a super-2 number, since 2×5302010365414572 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (530201036541467) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265100518270728 + 265100518270729.

It is an arithmetic number, because the mean of its divisors is an integer number (265100518270729).

Almost surely, 2530201036541457 is an apocalyptic number.

It is an amenable number.

530201036541457 is a deficient number, since it is larger than the sum of its proper divisors (1).

530201036541457 is an equidigital number, since it uses as much as digits as its factorization.

530201036541457 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1512000, while the sum is 46.

The spelling of 530201036541457 in words is "five hundred thirty trillion, two hundred one billion, thirty-six million, five hundred forty-one thousand, four hundred fifty-seven".