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530201112000 = 2635373155959
BaseRepresentation
bin1111011011100100111…
…00101110110111000000
31212200112121221011102020
413231302130232313000
532141322441041000
61043323201521440
753206610043510
oct7556234566700
91780477834366
10530201112000
1119494778399a
128690b343280
133acc8099351
141b93a25d840
15dbd2235ba0
hex7b7272edc0

530201112000 has 224 divisors, whose sum is σ = 2000828144640. Its totient is φ = 121188787200.

The previous prime is 530201111969. The next prime is 530201112013. The reversal of 530201112000 is 211102035.

It is a tau number, because it is divible by the number of its divisors (224).

It is a super-2 number, since 2×5302011120002 (a number of 24 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1409980 + ... + 1745979.

Almost surely, 2530201112000 is an apocalyptic number.

530201112000 is a gapful number since it is divisible by the number (50) formed by its first and last digit.

It is an amenable number.

530201112000 is an abundant number, since it is smaller than the sum of its proper divisors (1470627032640).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

530201112000 is a wasteful number, since it uses less digits than its factorization.

530201112000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3155996 (or 3155976 counting only the distinct ones).

The product of its (nonzero) digits is 60, while the sum is 15.

Adding to 530201112000 its reverse (211102035), we get a palindrome (530412214035).

The spelling of 530201112000 in words is "five hundred thirty billion, two hundred one million, one hundred twelve thousand".