Base | Representation |
---|---|
bin | 111100010001101110010101… |
… | …1000100101010111101001000 |
3 | 2120112021202212122222022011222 |
4 | 1320203130223010222331020 |
5 | 1023443310233402342440 |
6 | 5115351121342141212 |
7 | 216451540454102165 |
oct | 17043345304527510 |
9 | 2515252778868158 |
10 | 530201550434120 |
11 | 143a3623a992134 |
12 | 4b570742581808 |
13 | 199aca3a3c2236 |
14 | 94cdc6b79906c |
15 | 4146b5bd092b5 |
hex | 1e2372b12af48 |
530201550434120 has 64 divisors (see below), whose sum is σ = 1199901608745840. Its totient is φ = 210845505945600.
The previous prime is 530201550434119. The next prime is 530201550434239. The reversal of 530201550434120 is 21434055102035.
It can be written as a sum of positive squares in 8 ways, for example, as 192033798355876 + 338167752078244 = 13857626^2 + 18389338^2 .
It is a super-2 number, since 2×5302015504341202 (a number of 30 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 157781060 + ... + 161106380.
Almost surely, 2530201550434120 is an apocalyptic number.
It is an amenable number.
530201550434120 is an abundant number, since it is smaller than the sum of its proper divisors (669700058311720).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
530201550434120 is a wasteful number, since it uses less digits than its factorization.
530201550434120 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3348546 (or 3348542 counting only the distinct ones).
The product of its (nonzero) digits is 72000, while the sum is 35.
The spelling of 530201550434120 in words is "five hundred thirty trillion, two hundred one billion, five hundred fifty million, four hundred thirty-four thousand, one hundred twenty".
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