Search a number
-
+
53021319961 is a prime number
BaseRepresentation
bin110001011000010100…
…010010001100011001
312001212010222010110011
4301120110102030121
51332041424214321
640205130521521
73554626532521
oct613024221431
9161763863404
1053021319961
11205391754a5
12a3388962a1
134ccc9aa40c
1427cdac6681
1515a4c4aae1
hexc58512319

53021319961 has 2 divisors, whose sum is σ = 53021319962. Its totient is φ = 53021319960.

The previous prime is 53021319959. The next prime is 53021320021. The reversal of 53021319961 is 16991312035.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 47585059600 + 5436260361 = 218140^2 + 73731^2 .

It is a cyclic number.

It is not a de Polignac number, because 53021319961 - 21 = 53021319959 is a prime.

It is a super-2 number, since 2×530213199612 (a number of 22 digits) contains 22 as substring.

Together with 53021319959, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (53021311961) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26510659980 + 26510659981.

It is an arithmetic number, because the mean of its divisors is an integer number (26510659981).

Almost surely, 253021319961 is an apocalyptic number.

It is an amenable number.

53021319961 is a deficient number, since it is larger than the sum of its proper divisors (1).

53021319961 is an equidigital number, since it uses as much as digits as its factorization.

53021319961 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 43740, while the sum is 40.

The spelling of 53021319961 in words is "fifty-three billion, twenty-one million, three hundred nineteen thousand, nine hundred sixty-one".