Base | Representation |
---|---|
bin | 110001011000010100… |
… | …011101110010100111 |
3 | 12001212011001112121111 |
4 | 301120110131302213 |
5 | 1332041432224323 |
6 | 40205131525451 |
7 | 3554630121151 |
oct | 613024356247 |
9 | 161764045544 |
10 | 53021367463 |
11 | 205391a8159 |
12 | a3388b9887 |
13 | 4ccc9c5c1c |
14 | 27cdad9ad1 |
15 | 15a4c59c0d |
hex | c5851dca7 |
53021367463 has 2 divisors, whose sum is σ = 53021367464. Its totient is φ = 53021367462.
The previous prime is 53021367407. The next prime is 53021367479. The reversal of 53021367463 is 36476312035.
53021367463 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 53021367463 - 225 = 52987813031 is a prime.
It is a super-2 number, since 2×530213674632 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53021367563) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26510683731 + 26510683732.
It is an arithmetic number, because the mean of its divisors is an integer number (26510683732).
Almost surely, 253021367463 is an apocalyptic number.
53021367463 is a deficient number, since it is larger than the sum of its proper divisors (1).
53021367463 is an equidigital number, since it uses as much as digits as its factorization.
53021367463 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 272160, while the sum is 40.
Adding to 53021367463 its reverse (36476312035), we get a palindrome (89497679498).
The spelling of 53021367463 in words is "fifty-three billion, twenty-one million, three hundred sixty-seven thousand, four hundred sixty-three".
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