Base | Representation |
---|---|
bin | 110001011000011011… |
… | …100000010111001011 |
3 | 12001212021112022012211 |
4 | 301120123200113023 |
5 | 1332042420304003 |
6 | 40205235245551 |
7 | 3554651605555 |
oct | 613033402713 |
9 | 161767468184 |
10 | 53023213003 |
11 | 2053a2487a2 |
12 | a3394498b7 |
13 | 50001c0c67 |
14 | 27d005a4d5 |
15 | 15a4ec196d |
hex | c586e05cb |
53023213003 has 2 divisors, whose sum is σ = 53023213004. Its totient is φ = 53023213002.
The previous prime is 53023212971. The next prime is 53023213021. The reversal of 53023213003 is 30031232035.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 53023213003 - 25 = 53023212971 is a prime.
It is a super-2 number, since 2×530232130032 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (53023213063) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26511606501 + 26511606502.
It is an arithmetic number, because the mean of its divisors is an integer number (26511606502).
Almost surely, 253023213003 is an apocalyptic number.
53023213003 is a deficient number, since it is larger than the sum of its proper divisors (1).
53023213003 is an equidigital number, since it uses as much as digits as its factorization.
53023213003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1620, while the sum is 22.
Adding to 53023213003 its reverse (30031232035), we get a palindrome (83054445038).
The spelling of 53023213003 in words is "fifty-three billion, twenty-three million, two hundred thirteen thousand, three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •