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53023345114001 is a prime number
BaseRepresentation
bin11000000111001011101011…
…01001100111101110010001
320221201222112002101012120212
430003211311221213232101
523422213302322122001
6304434331035413505
714111544631032113
oct1403456551475621
9227658462335525
1053023345114001
1115993090001509
125b44342bb4295
1323781069772b2
14d144b4b873b3
1561e3d3b347bb
hex303975a67b91

53023345114001 has 2 divisors, whose sum is σ = 53023345114002. Its totient is φ = 53023345114000.

The previous prime is 53023345113967. The next prime is 53023345114027. The reversal of 53023345114001 is 10041154332035.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 44989952577025 + 8033392536976 = 6707455^2 + 2834324^2 .

It is a cyclic number.

It is not a de Polignac number, because 53023345114001 - 222 = 53023340919697 is a prime.

It is a super-2 number, since 2×530233451140012 (a number of 28 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (53023345119001) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26511672557000 + 26511672557001.

It is an arithmetic number, because the mean of its divisors is an integer number (26511672557001).

Almost surely, 253023345114001 is an apocalyptic number.

It is an amenable number.

53023345114001 is a deficient number, since it is larger than the sum of its proper divisors (1).

53023345114001 is an equidigital number, since it uses as much as digits as its factorization.

53023345114001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 21600, while the sum is 32.

Adding to 53023345114001 its reverse (10041154332035), we get a palindrome (63064499446036).

The spelling of 53023345114001 in words is "fifty-three trillion, twenty-three billion, three hundred forty-five million, one hundred fourteen thousand, one".