Base | Representation |
---|---|
bin | 111100010010000001011011… |
… | …0010111010000010000101111 |
3 | 2120112102200200102220211222222 |
4 | 1320210002312113100100233 |
5 | 1023444443211230403312 |
6 | 5115422021102425555 |
7 | 216454521332041406 |
oct | 17044026627202057 |
9 | 2515380612824888 |
10 | 530242542044207 |
11 | 143a51665653543 |
12 | 4b5786825922bb |
13 | 199b3870a34c15 |
14 | 94d1c3992c63d |
15 | 4147c5a8b6672 |
hex | 1e240b65d042f |
530242542044207 has 32 divisors (see below), whose sum is σ = 566489149873920. Its totient is φ = 494846989620480.
The previous prime is 530242542044183. The next prime is 530242542044209. The reversal of 530242542044207 is 702440245242035.
It is a happy number.
It is a cyclic number.
It is not a de Polignac number, because 530242542044207 - 222 = 530242537849903 is a prime.
It is a super-2 number, since 2×5302425420442072 (a number of 30 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (530242542044209) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 5064684953 + ... + 5064789645.
It is an arithmetic number, because the mean of its divisors is an integer number (17702785933560).
Almost surely, 2530242542044207 is an apocalyptic number.
530242542044207 is a deficient number, since it is larger than the sum of its proper divisors (36246607829713).
530242542044207 is a wasteful number, since it uses less digits than its factorization.
530242542044207 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 109223.
The product of its (nonzero) digits is 2150400, while the sum is 44.
The spelling of 530242542044207 in words is "five hundred thirty trillion, two hundred forty-two billion, five hundred forty-two million, forty-four thousand, two hundred seven".
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