Base | Representation |
---|---|
bin | 1001111000000110… |
… | …01101010001001001 |
3 | 111200112110220122221 |
4 | 10330003031101021 |
5 | 41324411103113 |
6 | 2234053414041 |
7 | 245254001521 |
oct | 47403152111 |
9 | 14615426587 |
10 | 5302441033 |
11 | 22810a947a |
12 | 103b93a321 |
13 | 666702796 |
14 | 38430c681 |
15 | 21079898d |
hex | 13c0cd449 |
5302441033 has 2 divisors, whose sum is σ = 5302441034. Its totient is φ = 5302441032.
The previous prime is 5302441007. The next prime is 5302441061. The reversal of 5302441033 is 3301442035.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3291546384 + 2010894649 = 57372^2 + 44843^2 .
It is a cyclic number.
It is not a de Polignac number, because 5302441033 - 213 = 5302432841 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5302440989 and 5302441007.
It is not a weakly prime, because it can be changed into another prime (5302441003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2651220516 + 2651220517.
It is an arithmetic number, because the mean of its divisors is an integer number (2651220517).
Almost surely, 25302441033 is an apocalyptic number.
It is an amenable number.
5302441033 is a deficient number, since it is larger than the sum of its proper divisors (1).
5302441033 is an equidigital number, since it uses as much as digits as its factorization.
5302441033 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4320, while the sum is 25.
The square root of 5302441033 is about 72817.8620463413. The cubic root of 5302441033 is about 1743.7810314866.
Adding to 5302441033 its reverse (3301442035), we get a palindrome (8603883068).
The spelling of 5302441033 in words is "five billion, three hundred two million, four hundred forty-one thousand, thirty-three".
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