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530244132313121 is a prime number
BaseRepresentation
bin111100010010000010001010…
…1001001101001100000100001
32120112102211210021021212211122
41320210010111021221200201
51024000004440333004441
65115422442551422025
7216454605622102052
oct17044042511514041
92515384707255748
10530244132313121
11143a52301289076
124b578a47084915
13199b3a65341645
1494d1d4ac0c729
154147d002e234b
hex1e24115269821

530244132313121 has 2 divisors, whose sum is σ = 530244132313122. Its totient is φ = 530244132313120.

The previous prime is 530244132313111. The next prime is 530244132313151. The reversal of 530244132313121 is 121313231442035.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 523502636832400 + 6741495480721 = 22880180^2 + 2596439^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-530244132313121 is a prime.

It is not a weakly prime, because it can be changed into another prime (530244132313111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265122066156560 + 265122066156561.

It is an arithmetic number, because the mean of its divisors is an integer number (265122066156561).

Almost surely, 2530244132313121 is an apocalyptic number.

It is an amenable number.

530244132313121 is a deficient number, since it is larger than the sum of its proper divisors (1).

530244132313121 is an equidigital number, since it uses as much as digits as its factorization.

530244132313121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 51840, while the sum is 35.

Adding to 530244132313121 its reverse (121313231442035), we get a palindrome (651557363755156).

The spelling of 530244132313121 in words is "five hundred thirty trillion, two hundred forty-four billion, one hundred thirty-two million, three hundred thirteen thousand, one hundred twenty-one".