Base | Representation |
---|---|
bin | 1111011011101010111… |
… | …00000000010110011101 |
3 | 1212200200010021121010211 |
4 | 13231311130000112131 |
5 | 32141423310100044 |
6 | 1043332152332421 |
7 | 53211056166562 |
oct | 7556534002635 |
9 | 1780603247124 |
10 | 530251253149 |
11 | 194973010762 |
12 | 869240a4111 |
13 | 3b0055a3a77 |
14 | 1b942b92869 |
15 | dbd683c634 |
hex | 7b7570059d |
530251253149 has 2 divisors, whose sum is σ = 530251253150. Its totient is φ = 530251253148.
The previous prime is 530251253143. The next prime is 530251253197. The reversal of 530251253149 is 941352152035.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 444295568025 + 85955685124 = 666555^2 + 293182^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-530251253149 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (530251253143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265125626574 + 265125626575.
It is an arithmetic number, because the mean of its divisors is an integer number (265125626575).
Almost surely, 2530251253149 is an apocalyptic number.
It is an amenable number.
530251253149 is a deficient number, since it is larger than the sum of its proper divisors (1).
530251253149 is an equidigital number, since it uses as much as digits as its factorization.
530251253149 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 162000, while the sum is 40.
The spelling of 530251253149 in words is "five hundred thirty billion, two hundred fifty-one million, two hundred fifty-three thousand, one hundred forty-nine".
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