Base | Representation |
---|---|
bin | 100110100101001100000… |
… | …1100011100110111100011 |
3 | 200202220210100020011210121 |
4 | 1031022120030130313203 |
5 | 1143334102004402232 |
6 | 15135542111541111 |
7 | 1055044650130243 |
oct | 115123014346743 |
9 | 20686710204717 |
10 | 5302543044067 |
11 | 1764883347475 |
12 | 717802b2a797 |
13 | 2c6048a13579 |
14 | 144904541b23 |
15 | 92de82aed97 |
hex | 4d29831cde3 |
5302543044067 has 2 divisors, whose sum is σ = 5302543044068. Its totient is φ = 5302543044066.
The previous prime is 5302543044011. The next prime is 5302543044077. The reversal of 5302543044067 is 7604403452035.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5302543044067 is a prime.
It is not a weakly prime, because it can be changed into another prime (5302543044077) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2651271522033 + 2651271522034.
It is an arithmetic number, because the mean of its divisors is an integer number (2651271522034).
Almost surely, 25302543044067 is an apocalyptic number.
5302543044067 is a deficient number, since it is larger than the sum of its proper divisors (1).
5302543044067 is an equidigital number, since it uses as much as digits as its factorization.
5302543044067 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1209600, while the sum is 43.
The spelling of 5302543044067 in words is "five trillion, three hundred two billion, five hundred forty-three million, forty-four thousand, sixty-seven".
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