Base | Representation |
---|---|
bin | 100110100101001100000… |
… | …1100011100110110101011 |
3 | 200202220210100020011201112 |
4 | 1031022120030130312223 |
5 | 1143334102004402021 |
6 | 15135542111540535 |
7 | 1055044650130133 |
oct | 115123014346653 |
9 | 20686710204645 |
10 | 5302543044011 |
11 | 1764883347424 |
12 | 717802b2a74b |
13 | 2c6048a13535 |
14 | 144904541ac3 |
15 | 92de82aed5b |
hex | 4d29831cdab |
5302543044011 has 2 divisors, whose sum is σ = 5302543044012. Its totient is φ = 5302543044010.
The previous prime is 5302543043989. The next prime is 5302543044067. The reversal of 5302543044011 is 1104403452035.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5302543044011 - 26 = 5302543043947 is a prime.
It is a super-3 number, since 3×53025430440113 (a number of 39 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (5302543044091) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2651271522005 + 2651271522006.
It is an arithmetic number, because the mean of its divisors is an integer number (2651271522006).
Almost surely, 25302543044011 is an apocalyptic number.
5302543044011 is a deficient number, since it is larger than the sum of its proper divisors (1).
5302543044011 is an equidigital number, since it uses as much as digits as its factorization.
5302543044011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 28800, while the sum is 32.
Adding to 5302543044011 its reverse (1104403452035), we get a palindrome (6406946496046).
The spelling of 5302543044011 in words is "five trillion, three hundred two billion, five hundred forty-three million, forty-four thousand, eleven".
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