Base | Representation |
---|---|
bin | 11000000111010001011010… |
… | …10110101000100001000111 |
3 | 20221202021110212202120021211 |
4 | 30003220231112220201013 |
5 | 23422241110322104023 |
6 | 304440000534152251 |
7 | 14112014203615066 |
oct | 1403505526504107 |
9 | 227667425676254 |
10 | 53026427144263 |
11 | 159944217aa461 |
12 | 5b44a631b2687 |
13 | 23784a8350041 |
14 | d146c82241dd |
15 | 61e5144cda0d |
hex | 303a2d5a8847 |
53026427144263 has 2 divisors, whose sum is σ = 53026427144264. Its totient is φ = 53026427144262.
The previous prime is 53026427144231. The next prime is 53026427144347. The reversal of 53026427144263 is 36244172462035.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 53026427144263 - 25 = 53026427144231 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53026427142263) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26513213572131 + 26513213572132.
It is an arithmetic number, because the mean of its divisors is an integer number (26513213572132).
Almost surely, 253026427144263 is an apocalyptic number.
53026427144263 is a deficient number, since it is larger than the sum of its proper divisors (1).
53026427144263 is an equidigital number, since it uses as much as digits as its factorization.
53026427144263 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5806080, while the sum is 49.
The spelling of 53026427144263 in words is "fifty-three trillion, twenty-six billion, four hundred twenty-seven million, one hundred forty-four thousand, two hundred sixty-three".
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