Base | Representation |
---|---|
bin | 110001011000101010… |
… | …100101101000001101 |
3 | 12001212112222011201021 |
4 | 301120222211220031 |
5 | 1332044423313413 |
6 | 40205500114141 |
7 | 3555030323512 |
oct | 613052455015 |
9 | 161775864637 |
10 | 53027166733 |
11 | 205414a9242 |
12 | a33a835951 |
13 | 5000c76748 |
14 | 27d07a9309 |
15 | 15a550318d |
hex | c58aa5a0d |
53027166733 has 2 divisors, whose sum is σ = 53027166734. Its totient is φ = 53027166732.
The previous prime is 53027166667. The next prime is 53027166737. The reversal of 53027166733 is 33766172035.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 34833743044 + 18193423689 = 186638^2 + 134883^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-53027166733 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 53027166733.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53027166737) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26513583366 + 26513583367.
It is an arithmetic number, because the mean of its divisors is an integer number (26513583367).
Almost surely, 253027166733 is an apocalyptic number.
It is an amenable number.
53027166733 is a deficient number, since it is larger than the sum of its proper divisors (1).
53027166733 is an equidigital number, since it uses as much as digits as its factorization.
53027166733 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 476280, while the sum is 43.
The spelling of 53027166733 in words is "fifty-three billion, twenty-seven million, one hundred sixty-six thousand, seven hundred thirty-three".
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