Base | Representation |
---|---|
bin | 100110100101011011010… |
… | …1001100110000100011011 |
3 | 200202222002221200110010122 |
4 | 1031022312221212010123 |
5 | 1143341123311003121 |
6 | 15140104523303455 |
7 | 1055063423156006 |
oct | 115126651460433 |
9 | 20688087613118 |
10 | 5303054000411 |
11 | 1765015807542 |
12 | 71792607ab8b |
13 | 2c60ca8335bb |
14 | 14495234a53d |
15 | 92e2808e5ab |
hex | 4d2b6a6611b |
5303054000411 has 2 divisors, whose sum is σ = 5303054000412. Its totient is φ = 5303054000410.
The previous prime is 5303054000393. The next prime is 5303054000429. The reversal of 5303054000411 is 1140004503035.
It is a balanced prime because it is at equal distance from previous prime (5303054000393) and next prime (5303054000429).
It is a cyclic number.
It is not a de Polignac number, because 5303054000411 - 238 = 5028176093467 is a prime.
It is a super-2 number, since 2×53030540004112 (a number of 26 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (5303054000471) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2651527000205 + 2651527000206.
It is an arithmetic number, because the mean of its divisors is an integer number (2651527000206).
Almost surely, 25303054000411 is an apocalyptic number.
5303054000411 is a deficient number, since it is larger than the sum of its proper divisors (1).
5303054000411 is an equidigital number, since it uses as much as digits as its factorization.
5303054000411 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3600, while the sum is 26.
Adding to 5303054000411 its reverse (1140004503035), we get a palindrome (6443058503446).
The spelling of 5303054000411 in words is "five trillion, three hundred three billion, fifty-four million, four hundred eleven", and thus it is an aban number.
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