Base | Representation |
---|---|
bin | 1111011011110001111… |
… | …00111010111011011101 |
3 | 1212200211020020002022122 |
4 | 13231320330322323131 |
5 | 32142033403311331 |
6 | 1043342100152325 |
7 | 53212403303306 |
oct | 7557074727335 |
9 | 1780736202278 |
10 | 530310213341 |
11 | 1949a3321397 |
12 | 8693b9986a5 |
13 | 3b01487865c |
14 | 1b94a93d7ad |
15 | dbdbad717b |
hex | 7b78f3aedd |
530310213341 has 2 divisors, whose sum is σ = 530310213342. Its totient is φ = 530310213340.
The previous prime is 530310213299. The next prime is 530310213371. The reversal of 530310213341 is 143312013035.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 461428111225 + 68882102116 = 679285^2 + 262454^2 .
It is a cyclic number.
It is not a de Polignac number, because 530310213341 - 222 = 530306019037 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 530310213341.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (530310213371) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265155106670 + 265155106671.
It is an arithmetic number, because the mean of its divisors is an integer number (265155106671).
Almost surely, 2530310213341 is an apocalyptic number.
It is an amenable number.
530310213341 is a deficient number, since it is larger than the sum of its proper divisors (1).
530310213341 is an equidigital number, since it uses as much as digits as its factorization.
530310213341 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3240, while the sum is 26.
Adding to 530310213341 its reverse (143312013035), we get a palindrome (673622226376).
The spelling of 530310213341 in words is "five hundred thirty billion, three hundred ten million, two hundred thirteen thousand, three hundred forty-one".
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