Base | Representation |
---|---|
bin | 1111011011110010011… |
… | …01000001101100001001 |
3 | 1212200211112011120210212 |
4 | 13231321031001230021 |
5 | 32142040443412322 |
6 | 1043342330450505 |
7 | 53212454216321 |
oct | 7557115015411 |
9 | 1780745146725 |
10 | 530314435337 |
11 | 1949a5745445 |
12 | 86941293a35 |
13 | 3b0156c628b |
14 | 1b94b31c281 |
15 | dbdc16d0e2 |
hex | 7b79341b09 |
530314435337 has 2 divisors, whose sum is σ = 530314435338. Its totient is φ = 530314435336.
The previous prime is 530314435333. The next prime is 530314435351. The reversal of 530314435337 is 733534413035.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 409012690681 + 121301744656 = 639541^2 + 348284^2 .
It is a cyclic number.
It is not a de Polignac number, because 530314435337 - 22 = 530314435333 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 530314435294 and 530314435303.
It is not a weakly prime, because it can be changed into another prime (530314435333) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265157217668 + 265157217669.
It is an arithmetic number, because the mean of its divisors is an integer number (265157217669).
Almost surely, 2530314435337 is an apocalyptic number.
It is an amenable number.
530314435337 is a deficient number, since it is larger than the sum of its proper divisors (1).
530314435337 is an equidigital number, since it uses as much as digits as its factorization.
530314435337 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 680400, while the sum is 41.
The spelling of 530314435337 in words is "five hundred thirty billion, three hundred fourteen million, four hundred thirty-five thousand, three hundred thirty-seven".
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