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530314435337 is a prime number
BaseRepresentation
bin1111011011110010011…
…01000001101100001001
31212200211112011120210212
413231321031001230021
532142040443412322
61043342330450505
753212454216321
oct7557115015411
91780745146725
10530314435337
111949a5745445
1286941293a35
133b0156c628b
141b94b31c281
15dbdc16d0e2
hex7b79341b09

530314435337 has 2 divisors, whose sum is σ = 530314435338. Its totient is φ = 530314435336.

The previous prime is 530314435333. The next prime is 530314435351. The reversal of 530314435337 is 733534413035.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 409012690681 + 121301744656 = 639541^2 + 348284^2 .

It is a cyclic number.

It is not a de Polignac number, because 530314435337 - 22 = 530314435333 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 530314435294 and 530314435303.

It is not a weakly prime, because it can be changed into another prime (530314435333) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265157217668 + 265157217669.

It is an arithmetic number, because the mean of its divisors is an integer number (265157217669).

Almost surely, 2530314435337 is an apocalyptic number.

It is an amenable number.

530314435337 is a deficient number, since it is larger than the sum of its proper divisors (1).

530314435337 is an equidigital number, since it uses as much as digits as its factorization.

530314435337 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 680400, while the sum is 41.

The spelling of 530314435337 in words is "five hundred thirty billion, three hundred fourteen million, four hundred thirty-five thousand, three hundred thirty-seven".