Base | Representation |
---|---|
bin | 111100010010100100001101… |
… | …1000011011010110000000111 |
3 | 2120112200211111200012012010220 |
4 | 1320211020123003122300013 |
5 | 1024002204204410142033 |
6 | 5115520213543115423 |
7 | 216463104503265333 |
oct | 17045103303326007 |
9 | 2515624450165126 |
10 | 530317245787143 |
11 | 143a8030a9a5271 |
12 | 4b58b050742b73 |
13 | 199ba917820bc9 |
14 | 94d56c51287c3 |
15 | 4149b7de0dbb3 |
hex | 1e2521b0dac07 |
530317245787143 has 32 divisors (see below), whose sum is σ = 770084898796800. Its totient is φ = 323339640454656.
The previous prime is 530317245787099. The next prime is 530317245787163. The reversal of 530317245787143 is 341787542713035.
It is a happy number.
It is not a de Polignac number, because 530317245787143 - 225 = 530317212232711 is a prime.
It is a super-2 number, since 2×5303172457871432 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (530317245787163) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 12674121 + ... + 34946642.
It is an arithmetic number, because the mean of its divisors is an integer number (24065153087400).
Almost surely, 2530317245787143 is an apocalyptic number.
530317245787143 is a deficient number, since it is larger than the sum of its proper divisors (239767653009657).
530317245787143 is a wasteful number, since it uses less digits than its factorization.
530317245787143 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 47627551.
The product of its (nonzero) digits is 59270400, while the sum is 60.
The spelling of 530317245787143 in words is "five hundred thirty trillion, three hundred seventeen billion, two hundred forty-five million, seven hundred eighty-seven thousand, one hundred forty-three".
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