Base | Representation |
---|---|
bin | 111100010010100110000111… |
… | …0110010101110111100101111 |
3 | 2120112201020001122212110212122 |
4 | 1320211030032302232330233 |
5 | 1024002241043233213002 |
6 | 5115522131422223155 |
7 | 216463311026422451 |
oct | 17045141662567457 |
9 | 2515636048773778 |
10 | 530321335054127 |
11 | 143a8201920a061 |
12 | 4b58b9b2124abb |
13 | 199bb119a98a06 |
14 | 94d59922782d1 |
15 | 4149d1ce186a2 |
hex | 1e2530ecaef2f |
530321335054127 has 2 divisors, whose sum is σ = 530321335054128. Its totient is φ = 530321335054126.
The previous prime is 530321335054081. The next prime is 530321335054183. The reversal of 530321335054127 is 721450533123035.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 530321335054127 - 216 = 530321334988591 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (530321335054727) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265160667527063 + 265160667527064.
It is an arithmetic number, because the mean of its divisors is an integer number (265160667527064).
Almost surely, 2530321335054127 is an apocalyptic number.
530321335054127 is a deficient number, since it is larger than the sum of its proper divisors (1).
530321335054127 is an equidigital number, since it uses as much as digits as its factorization.
530321335054127 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1134000, while the sum is 44.
The spelling of 530321335054127 in words is "five hundred thirty trillion, three hundred twenty-one billion, three hundred thirty-five million, fifty-four thousand, one hundred twenty-seven".
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