Base | Representation |
---|---|
bin | 110001011000111110… |
… | …101000011111010101 |
3 | 12001212220212010200002 |
4 | 301120332220133111 |
5 | 1332102244440313 |
6 | 40210204501045 |
7 | 3555123100163 |
oct | 613076503725 |
9 | 161786763602 |
10 | 53032421333 |
11 | 20544468091 |
12 | a34054a785 |
13 | 5002096388 |
14 | 27d1376233 |
15 | 15a5be0058 |
hex | c58fa87d5 |
53032421333 has 2 divisors, whose sum is σ = 53032421334. Its totient is φ = 53032421332.
The previous prime is 53032421317. The next prime is 53032421347. The reversal of 53032421333 is 33312423035.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 28778408164 + 24254013169 = 169642^2 + 155737^2 .
It is a cyclic number.
It is not a de Polignac number, because 53032421333 - 24 = 53032421317 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 53032421296 and 53032421305.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53032451333) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26516210666 + 26516210667.
It is an arithmetic number, because the mean of its divisors is an integer number (26516210667).
Almost surely, 253032421333 is an apocalyptic number.
It is an amenable number.
53032421333 is a deficient number, since it is larger than the sum of its proper divisors (1).
53032421333 is an equidigital number, since it uses as much as digits as its factorization.
53032421333 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 19440, while the sum is 29.
Adding to 53032421333 its reverse (33312423035), we get a palindrome (86344844368).
The spelling of 53032421333 in words is "fifty-three billion, thirty-two million, four hundred twenty-one thousand, three hundred thirty-three".
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