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530325212437 is a prime number
BaseRepresentation
bin1111011011110011101…
…10001000110100010101
31212200212021110010012201
413231321312020310111
532142101223244222
61043343353444501
753212644633406
oct7557166106425
91780767403181
10530325212437
11194a00836439
1286944a10731
133b0179ca767
141b94c9259ad
15dbdd09b427
hex7b79d88d15

530325212437 has 2 divisors, whose sum is σ = 530325212438. Its totient is φ = 530325212436.

The previous prime is 530325212411. The next prime is 530325212471. The reversal of 530325212437 is 734212523035.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 396867240676 + 133457971761 = 629974^2 + 365319^2 .

It is a cyclic number.

It is not a de Polignac number, because 530325212437 - 227 = 530190994709 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 530325212396 and 530325212405.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (530325212537) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265162606218 + 265162606219.

It is an arithmetic number, because the mean of its divisors is an integer number (265162606219).

Almost surely, 2530325212437 is an apocalyptic number.

It is an amenable number.

530325212437 is a deficient number, since it is larger than the sum of its proper divisors (1).

530325212437 is an equidigital number, since it uses as much as digits as its factorization.

530325212437 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 151200, while the sum is 37.

The spelling of 530325212437 in words is "five hundred thirty billion, three hundred twenty-five million, two hundred twelve thousand, four hundred thirty-seven".