Base | Representation |
---|---|
bin | 1001111000001101… |
… | …00001101111100111 |
3 | 111200121010010111100 |
4 | 10330012201233213 |
5 | 41330121430320 |
6 | 2234124211143 |
7 | 245264255040 |
oct | 47406415747 |
9 | 14617103440 |
10 | 5303311335 |
11 | 2281643333 |
12 | 1040099ab3 |
13 | 66694895a |
14 | 3844978c7 |
15 | 2108bb790 |
hex | 13c1a1be7 |
5303311335 has 48 divisors (see below), whose sum is σ = 10552029696. Its totient is φ = 2413658304.
The previous prime is 5303311301. The next prime is 5303311393. The reversal of 5303311335 is 5331133035.
It is a happy number.
It is not a de Polignac number, because 5303311335 - 26 = 5303311271 is a prime.
It is a super-2 number, since 2×53033113352 = 56250222231878964450, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 5303311299 and 5303311308.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 34422 + ... + 108588.
It is an arithmetic number, because the mean of its divisors is an integer number (219833952).
Almost surely, 25303311335 is an apocalyptic number.
5303311335 is a deficient number, since it is larger than the sum of its proper divisors (5248718361).
5303311335 is a wasteful number, since it uses less digits than its factorization.
5303311335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 74412 (or 74409 counting only the distinct ones).
The product of its (nonzero) digits is 6075, while the sum is 27.
The square root of 5303311335 is about 72823.8376838244. The cubic root of 5303311335 is about 1743.8764298819.
The spelling of 5303311335 in words is "five billion, three hundred three million, three hundred eleven thousand, three hundred thirty-five".
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