Base | Representation |
---|---|
bin | 100110100101100110101… |
… | …0100100001001100110101 |
3 | 200210000002110101021121210 |
4 | 1031023031110201030311 |
5 | 1143342413143221123 |
6 | 15140210351432033 |
7 | 1055106022123032 |
oct | 115131524411465 |
9 | 20700073337553 |
10 | 5303434351413 |
11 | 17651a0481910 |
12 | 717a11525619 |
13 | 2c615b585473 |
14 | 14498aa78389 |
15 | 92e4b670e93 |
hex | 4d2cd521335 |
5303434351413 has 128 divisors (see below), whose sum is σ = 8055919872000. Its totient is φ = 3075756364800.
The previous prime is 5303434351393. The next prime is 5303434351433. The reversal of 5303434351413 is 3141534343035.
It is an interprime number because it is at equal distance from previous prime (5303434351393) and next prime (5303434351433).
It is a de Polignac number, because none of the positive numbers 2k-5303434351413 is a prime.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5303434351433) by changing a digit.
It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 5319392031 + ... + 5319393027.
It is an arithmetic number, because the mean of its divisors is an integer number (62936874000).
Almost surely, 25303434351413 is an apocalyptic number.
It is an amenable number.
5303434351413 is a deficient number, since it is larger than the sum of its proper divisors (2752485520587).
5303434351413 is a wasteful number, since it uses less digits than its factorization.
5303434351413 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1523.
The product of its (nonzero) digits is 388800, while the sum is 39.
Adding to 5303434351413 its reverse (3141534343035), we get a palindrome (8444968694448).
The spelling of 5303434351413 in words is "five trillion, three hundred three billion, four hundred thirty-four million, three hundred fifty-one thousand, four hundred thirteen".
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