Base | Representation |
---|---|
bin | 100110100101101000101… |
… | …1100000111011101011001 |
3 | 200210000021021101221210112 |
4 | 1031023101130013131121 |
5 | 1143343033340430433 |
6 | 15140221300454105 |
7 | 1055110521352325 |
oct | 115132134073531 |
9 | 20700237357715 |
10 | 5303503451993 |
11 | 176522648912a |
12 | 717a306aa335 |
13 | 2c616c99a796 |
14 | 144995d04985 |
15 | 92e52770348 |
hex | 4d2d1707759 |
5303503451993 has 2 divisors, whose sum is σ = 5303503451994. Its totient is φ = 5303503451992.
The previous prime is 5303503451963. The next prime is 5303503452019. The reversal of 5303503451993 is 3991543053035.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4212005068489 + 1091498383504 = 2052317^2 + 1044748^2 .
It is a cyclic number.
It is not a de Polignac number, because 5303503451993 - 26 = 5303503451929 is a prime.
It is not a weakly prime, because it can be changed into another prime (5303503451923) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2651751725996 + 2651751725997.
It is an arithmetic number, because the mean of its divisors is an integer number (2651751725997).
Almost surely, 25303503451993 is an apocalyptic number.
It is an amenable number.
5303503451993 is a deficient number, since it is larger than the sum of its proper divisors (1).
5303503451993 is an equidigital number, since it uses as much as digits as its factorization.
5303503451993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3280500, while the sum is 50.
The spelling of 5303503451993 in words is "five trillion, three hundred three billion, five hundred three million, four hundred fifty-one thousand, nine hundred ninety-three".
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