Base | Representation |
---|---|
bin | 100110100101101000101… |
… | …1100000111011101110011 |
3 | 200210000021021101221211111 |
4 | 1031023101130013131303 |
5 | 1143343033340431034 |
6 | 15140221300454151 |
7 | 1055110521352363 |
oct | 115132134073563 |
9 | 20700237357744 |
10 | 5303503452019 |
11 | 1765226489153 |
12 | 717a306aa357 |
13 | 2c616c99a7b6 |
14 | 144995d049a3 |
15 | 92e52770364 |
hex | 4d2d1707773 |
5303503452019 has 2 divisors, whose sum is σ = 5303503452020. Its totient is φ = 5303503452018.
The previous prime is 5303503451993. The next prime is 5303503452029. The reversal of 5303503452019 is 9102543053035.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5303503452019 - 27 = 5303503451891 is a prime.
It is a super-2 number, since 2×53035034520192 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5303503452029) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2651751726009 + 2651751726010.
It is an arithmetic number, because the mean of its divisors is an integer number (2651751726010).
Almost surely, 25303503452019 is an apocalyptic number.
5303503452019 is a deficient number, since it is larger than the sum of its proper divisors (1).
5303503452019 is an equidigital number, since it uses as much as digits as its factorization.
5303503452019 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 243000, while the sum is 40.
The spelling of 5303503452019 in words is "five trillion, three hundred three billion, five hundred three million, four hundred fifty-two thousand, nineteen".
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