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53035104031 = 7138315674481
BaseRepresentation
bin110001011001001000…
…110111011100011111
312001220002220102122021
4301121020313130133
51332103441312111
640210342201011
73555154642360
oct613110673437
9161802812567
1053035104031
1120545a2a698
12a341423167
1350027c5480
1427d1873b67
1515a606ed71
hexc5923771f

53035104031 has 32 divisors (see below), whose sum is σ = 66117316608. Its totient is φ = 41420574720.

The previous prime is 53035104013. The next prime is 53035104107. The reversal of 53035104031 is 13040153035.

It is not a de Polignac number, because 53035104031 - 219 = 53034579743 is a prime.

It is a super-2 number, since 2×530351040312 (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 53035103987 and 53035104005.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (53035104011) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 11833311 + ... + 11837791.

It is an arithmetic number, because the mean of its divisors is an integer number (2066166144).

Almost surely, 253035104031 is an apocalyptic number.

53035104031 is a deficient number, since it is larger than the sum of its proper divisors (13082212577).

53035104031 is a wasteful number, since it uses less digits than its factorization.

53035104031 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6151.

The product of its (nonzero) digits is 2700, while the sum is 25.

Adding to 53035104031 its reverse (13040153035), we get a palindrome (66075257066).

The spelling of 53035104031 in words is "fifty-three billion, thirty-five million, one hundred four thousand, thirty-one".

Divisors: 1 7 13 83 91 581 1079 1567 4481 7553 10969 20371 31367 58253 130061 142597 371923 407771 910427 1690793 2603461 4834999 7021727 11835551 33844993 49152089 91282451 582803341 638977157 4079623387 7576443433 53035104031