Base | Representation |
---|---|
bin | 110001011001001000… |
… | …110111011100011111 |
3 | 12001220002220102122021 |
4 | 301121020313130133 |
5 | 1332103441312111 |
6 | 40210342201011 |
7 | 3555154642360 |
oct | 613110673437 |
9 | 161802812567 |
10 | 53035104031 |
11 | 20545a2a698 |
12 | a341423167 |
13 | 50027c5480 |
14 | 27d1873b67 |
15 | 15a606ed71 |
hex | c5923771f |
53035104031 has 32 divisors (see below), whose sum is σ = 66117316608. Its totient is φ = 41420574720.
The previous prime is 53035104013. The next prime is 53035104107. The reversal of 53035104031 is 13040153035.
It is not a de Polignac number, because 53035104031 - 219 = 53034579743 is a prime.
It is a super-2 number, since 2×530351040312 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 53035103987 and 53035104005.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53035104011) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 11833311 + ... + 11837791.
It is an arithmetic number, because the mean of its divisors is an integer number (2066166144).
Almost surely, 253035104031 is an apocalyptic number.
53035104031 is a deficient number, since it is larger than the sum of its proper divisors (13082212577).
53035104031 is a wasteful number, since it uses less digits than its factorization.
53035104031 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6151.
The product of its (nonzero) digits is 2700, while the sum is 25.
Adding to 53035104031 its reverse (13040153035), we get a palindrome (66075257066).
The spelling of 53035104031 in words is "fifty-three billion, thirty-five million, one hundred four thousand, thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •