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530353500041 is a prime number
BaseRepresentation
bin1111011011110111000…
…10000010111110001001
31212200221020200021111202
413231323202002332021
532142130444000131
61043350244033545
753213440240511
oct7557342027611
91780836607452
10530353500041
11194a157a7322
12869523928b5
133b0208231a1
141b9525aa841
15dbe07d7bcb
hex7b7b882f89

530353500041 has 2 divisors, whose sum is σ = 530353500042. Its totient is φ = 530353500040.

The previous prime is 530353499999. The next prime is 530353500043. The reversal of 530353500041 is 140005353035.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 474004710400 + 56348789641 = 688480^2 + 237379^2 .

It is a cyclic number.

It is not a de Polignac number, because 530353500041 - 222 = 530349305737 is a prime.

Together with 530353500043, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 530353499977 and 530353500013.

It is not a weakly prime, because it can be changed into another prime (530353500043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265176750020 + 265176750021.

It is an arithmetic number, because the mean of its divisors is an integer number (265176750021).

Almost surely, 2530353500041 is an apocalyptic number.

It is an amenable number.

530353500041 is a deficient number, since it is larger than the sum of its proper divisors (1).

530353500041 is an equidigital number, since it uses as much as digits as its factorization.

530353500041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 13500, while the sum is 29.

Adding to 530353500041 its reverse (140005353035), we get a palindrome (670358853076).

The spelling of 530353500041 in words is "five hundred thirty billion, three hundred fifty-three million, five hundred thousand, forty-one".