Base | Representation |
---|---|
bin | 1111011011110111000… |
… | …11111110010010010101 |
3 | 1212200221021121221101011 |
4 | 13231323203332102111 |
5 | 32142131111131031 |
6 | 1043350302532221 |
7 | 53213444443222 |
oct | 7557343762225 |
9 | 1780837557334 |
10 | 530354005141 |
11 | 194a16011864 |
12 | 86952597071 |
13 | 3b02096c06c |
14 | 1b95269c949 |
15 | dbe08876b1 |
hex | 7b7b8fe495 |
530354005141 has 2 divisors, whose sum is σ = 530354005142. Its totient is φ = 530354005140.
The previous prime is 530354005043. The next prime is 530354005163. The reversal of 530354005141 is 141500453035.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 402228666225 + 128125338916 = 634215^2 + 357946^2 .
It is a cyclic number.
It is not a de Polignac number, because 530354005141 - 211 = 530354003093 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (530354005171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265177002570 + 265177002571.
It is an arithmetic number, because the mean of its divisors is an integer number (265177002571).
Almost surely, 2530354005141 is an apocalyptic number.
It is an amenable number.
530354005141 is a deficient number, since it is larger than the sum of its proper divisors (1).
530354005141 is an equidigital number, since it uses as much as digits as its factorization.
530354005141 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18000, while the sum is 31.
Adding to 530354005141 its reverse (141500453035), we get a palindrome (671854458176).
The spelling of 530354005141 in words is "five hundred thirty billion, three hundred fifty-four million, five thousand, one hundred forty-one".
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