5303541130031 has 2 divisors, whose sum is σ = 5303541130032. Its totient is φ = 5303541130030.

The previous prime is 5303541130021. The next prime is 5303541130039. The reversal of 5303541130031 is 1300311453035.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 5303541130031 - 2¹⁸ = 5303540867887 is a prime.

It is a super-3 number, since 3×5303541130031³ (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 5303541129976 and 5303541130003.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5303541130039) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2651770565015 + 2651770565016.

It is an arithmetic number, because the mean of its divisors is an integer number (2651770565016).

Almost surely, 2^{5303541130031} is an apocalyptic number.

5303541130031 is a deficient number, since it is larger than the sum of its proper divisors (1).

5303541130031 is an equidigital number, since it uses as much as digits as its factorization.

5303541130031 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8100, while the sum is 29.

Adding to 5303541130031 its reverse (1300311453035), we get a palindrome (6603852583066).

The spelling of 5303541130031 in words is "five trillion, three hundred three billion, five hundred forty-one million, one hundred thirty thousand, thirty-one".