Base | Representation |
---|---|
bin | 1111011011110111001… |
… | …00011111010001000111 |
3 | 1212200221021212210200111 |
4 | 13231323210133101013 |
5 | 32142131124441411 |
6 | 1043350305453451 |
7 | 53213445545116 |
oct | 7557344372107 |
9 | 1780837783614 |
10 | 530354140231 |
11 | 194a160a4303 |
12 | 86952641287 |
13 | 3b0209b86b6 |
14 | 1b9526d5c7d |
15 | dbe08b2721 |
hex | 7b7b91f447 |
530354140231 has 2 divisors, whose sum is σ = 530354140232. Its totient is φ = 530354140230.
The previous prime is 530354140189. The next prime is 530354140237. The reversal of 530354140231 is 132041453035.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 530354140231 - 235 = 495994401863 is a prime.
It is a super-2 number, since 2×5303541402312 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 530354140193 and 530354140202.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (530354140237) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265177070115 + 265177070116.
It is an arithmetic number, because the mean of its divisors is an integer number (265177070116).
Almost surely, 2530354140231 is an apocalyptic number.
530354140231 is a deficient number, since it is larger than the sum of its proper divisors (1).
530354140231 is an equidigital number, since it uses as much as digits as its factorization.
530354140231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 21600, while the sum is 31.
Adding to 530354140231 its reverse (132041453035), we get a palindrome (662395593266).
The spelling of 530354140231 in words is "five hundred thirty billion, three hundred fifty-four million, one hundred forty thousand, two hundred thirty-one".
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