Base | Representation |
---|---|
bin | 1111011011111100100… |
… | …11110110111110100111 |
3 | 1212201001111101102212000 |
4 | 13231332103312332213 |
5 | 32142224412100201 |
6 | 1043355031100343 |
7 | 53214544366161 |
oct | 7557623667647 |
9 | 1781044342760 |
10 | 530400112551 |
11 | 194a3a043a61 |
12 | 86965b116b3 |
13 | 3b02a39375a |
14 | 1b958861931 |
15 | dbe4943d86 |
hex | 7b7e4f6fa7 |
530400112551 has 64 divisors (see below), whose sum is σ = 816564672000. Its totient is φ = 340030828800.
The previous prime is 530400112513. The next prime is 530400112579. The reversal of 530400112551 is 155211004035.
530400112551 is a `hidden beast` number, since 5 + 3 + 0 + 400 + 1 + 1 + 255 + 1 = 666.
It is not a de Polignac number, because 530400112551 - 214 = 530400096167 is a prime.
It is a super-2 number, since 2×5304001125512 (a number of 24 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (530400112651) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 21595260 + ... + 21619806.
It is an arithmetic number, because the mean of its divisors is an integer number (12758823000).
Almost surely, 2530400112551 is an apocalyptic number.
530400112551 is a deficient number, since it is larger than the sum of its proper divisors (286164559449).
530400112551 is a wasteful number, since it uses less digits than its factorization.
530400112551 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 24877 (or 24871 counting only the distinct ones).
The product of its (nonzero) digits is 3000, while the sum is 27.
Adding to 530400112551 its reverse (155211004035), we get a palindrome (685611116586).
The spelling of 530400112551 in words is "five hundred thirty billion, four hundred million, one hundred twelve thousand, five hundred fifty-one".
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