Base | Representation |
---|---|
bin | 11111100111010… |
… | …100001111000001 |
3 | 1100222001010021121 |
4 | 133213110033001 |
5 | 2041240301233 |
6 | 124344152241 |
7 | 16100220151 |
oct | 3747241701 |
9 | 1328033247 |
10 | 530400193 |
11 | 252440574 |
12 | 129768681 |
13 | 85b6a28b |
14 | 5062a761 |
15 | 3187092d |
hex | 1f9d43c1 |
530400193 has 2 divisors, whose sum is σ = 530400194. Its totient is φ = 530400192.
The previous prime is 530400151. The next prime is 530400229. The reversal of 530400193 is 391004035.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 506115009 + 24285184 = 22497^2 + 4928^2 .
It is a cyclic number.
It is not a de Polignac number, because 530400193 - 217 = 530269121 is a prime.
It is not a weakly prime, because it can be changed into another prime (530400103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265200096 + 265200097.
It is an arithmetic number, because the mean of its divisors is an integer number (265200097).
Almost surely, 2530400193 is an apocalyptic number.
It is an amenable number.
530400193 is a deficient number, since it is larger than the sum of its proper divisors (1).
530400193 is an equidigital number, since it uses as much as digits as its factorization.
530400193 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1620, while the sum is 25.
The square root of 530400193 is about 23030.4188628865. The cubic root of 530400193 is about 809.4708696842.
The spelling of 530400193 in words is "five hundred thirty million, four hundred thousand, one hundred ninety-three".
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