5304043307 has 2 divisors, whose sum is σ = 5304043308. Its totient is φ = 5304043306.

The previous prime is 5304043243. The next prime is 5304043313. The reversal of 5304043307 is 7033404035.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 5304043307 - 2⁶ = 5304043243 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 5304043307.

It is not a weakly prime, because it can be changed into another prime (5304043907) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2652021653 + 2652021654.

It is an arithmetic number, because the mean of its divisors is an integer number (2652021654).

Almost surely, 2^5304043307 is an apocalyptic number.

5304043307 is a deficient number, since it is larger than the sum of its proper divisors (1).

5304043307 is an equidigital number, since it uses as much as digits as its factorization.

5304043307 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15120, while the sum is 29.

The square root of 5304043307 is about 72828.8631450471. The cubic root of 5304043307 is about 1743.9566571157.

The spelling of 5304043307 in words is "five billion, three hundred four million, forty-three thousand, three hundred seven".