Base | Representation |
---|---|
bin | 110001011001011101… |
… | …010101011110000011 |
3 | 12001220111000001012211 |
4 | 301121131111132003 |
5 | 1332111330014031 |
6 | 40211053202551 |
7 | 3555251361313 |
oct | 613135253603 |
9 | 161814001184 |
10 | 53040469891 |
11 | 20548a65092 |
12 | a343190457 |
13 | 5003953936 |
14 | 27d246d443 |
15 | 15a677ebb1 |
hex | c59755783 |
53040469891 has 2 divisors, whose sum is σ = 53040469892. Its totient is φ = 53040469890.
The previous prime is 53040469871. The next prime is 53040469903. The reversal of 53040469891 is 19896404035.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 53040469891 - 213 = 53040461699 is a prime.
It is not a weakly prime, because it can be changed into another prime (53040469871) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26520234945 + 26520234946.
It is an arithmetic number, because the mean of its divisors is an integer number (26520234946).
Almost surely, 253040469891 is an apocalyptic number.
53040469891 is a deficient number, since it is larger than the sum of its proper divisors (1).
53040469891 is an equidigital number, since it uses as much as digits as its factorization.
53040469891 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 933120, while the sum is 49.
The spelling of 53040469891 in words is "fifty-three billion, forty million, four hundred sixty-nine thousand, eight hundred ninety-one".
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