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53042400461 is a prime number
BaseRepresentation
bin110001011001100100…
…101100110011001101
312001220121122010110102
4301121210230303031
51332112323303321
640211202420445
73555303651641
oct613144546315
9161817563412
1053042400461
112054a0635a6
12a343961725
13500417b59b
1427d2812c21
1515a6a11c0b
hexc5992cccd

53042400461 has 2 divisors, whose sum is σ = 53042400462. Its totient is φ = 53042400460.

The previous prime is 53042400431. The next prime is 53042400503. The reversal of 53042400461 is 16400424035.

53042400461 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 34761738025 + 18280662436 = 186445^2 + 135206^2 .

It is a cyclic number.

It is not a de Polignac number, because 53042400461 - 234 = 35862531277 is a prime.

It is a super-3 number, since 3×530424004613 (a number of 33 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (53042400401) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26521200230 + 26521200231.

It is an arithmetic number, because the mean of its divisors is an integer number (26521200231).

Almost surely, 253042400461 is an apocalyptic number.

It is an amenable number.

53042400461 is a deficient number, since it is larger than the sum of its proper divisors (1).

53042400461 is an equidigital number, since it uses as much as digits as its factorization.

53042400461 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 11520, while the sum is 29.

Adding to 53042400461 its reverse (16400424035), we get a palindrome (69442824496).

The spelling of 53042400461 in words is "fifty-three billion, forty-two million, four hundred thousand, four hundred sixty-one".