Base | Representation |
---|---|
bin | 110001011001100100… |
… | …101100110011001101 |
3 | 12001220121122010110102 |
4 | 301121210230303031 |
5 | 1332112323303321 |
6 | 40211202420445 |
7 | 3555303651641 |
oct | 613144546315 |
9 | 161817563412 |
10 | 53042400461 |
11 | 2054a0635a6 |
12 | a343961725 |
13 | 500417b59b |
14 | 27d2812c21 |
15 | 15a6a11c0b |
hex | c5992cccd |
53042400461 has 2 divisors, whose sum is σ = 53042400462. Its totient is φ = 53042400460.
The previous prime is 53042400431. The next prime is 53042400503. The reversal of 53042400461 is 16400424035.
53042400461 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 34761738025 + 18280662436 = 186445^2 + 135206^2 .
It is a cyclic number.
It is not a de Polignac number, because 53042400461 - 234 = 35862531277 is a prime.
It is a super-3 number, since 3×530424004613 (a number of 33 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53042400401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26521200230 + 26521200231.
It is an arithmetic number, because the mean of its divisors is an integer number (26521200231).
Almost surely, 253042400461 is an apocalyptic number.
It is an amenable number.
53042400461 is a deficient number, since it is larger than the sum of its proper divisors (1).
53042400461 is an equidigital number, since it uses as much as digits as its factorization.
53042400461 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11520, while the sum is 29.
Adding to 53042400461 its reverse (16400424035), we get a palindrome (69442824496).
The spelling of 53042400461 in words is "fifty-three billion, forty-two million, four hundred thousand, four hundred sixty-one".
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