53044151 has 2 divisors, whose sum is σ = 53044152. Its totient is φ = 53044150.

The previous prime is 53044133. The next prime is 53044157. The reversal of 53044151 is 15144035.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-53044151 is a prime.

It is a Sophie Germain prime.

It is a Chen prime.

It is equal to p_3172541 and since 53044151 and 3172541 have the same sum of digits, it is a Honaker prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (53044157) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26522075 + 26522076.

It is an arithmetic number, because the mean of its divisors is an integer number (26522076).

Almost surely, 2^53044151 is an apocalyptic number.

53044151 is a deficient number, since it is larger than the sum of its proper divisors (1).

53044151 is an equidigital number, since it uses as much as digits as its factorization.

53044151 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1200, while the sum is 23.

The square root of 53044151 is about 7283.1415611671. The cubic root of 53044151 is about 375.7328507317.

Adding to 53044151 its reverse (15144035), we get a palindrome (68188186).

The spelling of 53044151 in words is "fifty-three million, forty-four thousand, one hundred fifty-one".