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5304430400431 is a prime number
BaseRepresentation
bin100110100110000100010…
…1100001001001110101111
3200210002122212121211000011
41031030020230021032233
51143401433140303211
615140453252314051
71055142505320031
oct115141054111657
920702585554004
105304430400431
111765661747218
1271804b012927
132c6289a3b196
14144a43077c51
1592ea8d21921
hex4d308b093af

5304430400431 has 2 divisors, whose sum is σ = 5304430400432. Its totient is φ = 5304430400430.

The previous prime is 5304430400363. The next prime is 5304430400603. The reversal of 5304430400431 is 1340040344035.

5304430400431 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5304430400431 is a prime.

It is a super-2 number, since 2×53044304004312 (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 5304430400393 and 5304430400402.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5304430400131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2652215200215 + 2652215200216.

It is an arithmetic number, because the mean of its divisors is an integer number (2652215200216).

Almost surely, 25304430400431 is an apocalyptic number.

5304430400431 is a deficient number, since it is larger than the sum of its proper divisors (1).

5304430400431 is an equidigital number, since it uses as much as digits as its factorization.

5304430400431 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 34560, while the sum is 31.

Adding to 5304430400431 its reverse (1340040344035), we get a palindrome (6644470744466).

The spelling of 5304430400431 in words is "five trillion, three hundred four billion, four hundred thirty million, four hundred thousand, four hundred thirty-one".