Base | Representation |
---|---|
bin | 110001011001101110… |
… | …100111010001001111 |
3 | 12001220210112011022202 |
4 | 301121232213101033 |
5 | 1332114004433442 |
6 | 40211334232115 |
7 | 3555335024402 |
oct | 613156472117 |
9 | 161823464282 |
10 | 53044999247 |
11 | 20550579059 |
12 | a3447b563b |
13 | 500487b426 |
14 | 27d2ccbd39 |
15 | 15a6d76c32 |
hex | c59ba744f |
53044999247 has 2 divisors, whose sum is σ = 53044999248. Its totient is φ = 53044999246.
The previous prime is 53044999223. The next prime is 53044999307. The reversal of 53044999247 is 74299944035.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-53044999247 is a prime.
It is a super-2 number, since 2×530449992472 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 53044999192 and 53044999201.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53044995247) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26522499623 + 26522499624.
It is an arithmetic number, because the mean of its divisors is an integer number (26522499624).
Almost surely, 253044999247 is an apocalyptic number.
53044999247 is a deficient number, since it is larger than the sum of its proper divisors (1).
53044999247 is an equidigital number, since it uses as much as digits as its factorization.
53044999247 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9797760, while the sum is 56.
The spelling of 53044999247 in words is "fifty-three billion, forty-four million, nine hundred ninety-nine thousand, two hundred forty-seven".
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