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53044999247 is a prime number
BaseRepresentation
bin110001011001101110…
…100111010001001111
312001220210112011022202
4301121232213101033
51332114004433442
640211334232115
73555335024402
oct613156472117
9161823464282
1053044999247
1120550579059
12a3447b563b
13500487b426
1427d2ccbd39
1515a6d76c32
hexc59ba744f

53044999247 has 2 divisors, whose sum is σ = 53044999248. Its totient is φ = 53044999246.

The previous prime is 53044999223. The next prime is 53044999307. The reversal of 53044999247 is 74299944035.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-53044999247 is a prime.

It is a super-2 number, since 2×530449992472 (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 53044999192 and 53044999201.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (53044995247) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26522499623 + 26522499624.

It is an arithmetic number, because the mean of its divisors is an integer number (26522499624).

Almost surely, 253044999247 is an apocalyptic number.

53044999247 is a deficient number, since it is larger than the sum of its proper divisors (1).

53044999247 is an equidigital number, since it uses as much as digits as its factorization.

53044999247 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9797760, while the sum is 56.

The spelling of 53044999247 in words is "fifty-three billion, forty-four million, nine hundred ninety-nine thousand, two hundred forty-seven".