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530450230333 is a prime number
BaseRepresentation
bin1111011100000010100…
…11000010110000111101
31212201011222200200112011
413232001103002300331
532142330224332313
61043404021211221
753216023364152
oct7560123026075
91781158620464
10530450230333
11194a65365211
128697a860b11
133b03789064a
141b96138a229
15dbe904393d
hex7b814c2c3d

530450230333 has 2 divisors, whose sum is σ = 530450230334. Its totient is φ = 530450230332.

The previous prime is 530450230327. The next prime is 530450230397. The reversal of 530450230333 is 333032054035.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 457276193284 + 73174037049 = 676222^2 + 270507^2 .

It is a cyclic number.

It is not a de Polignac number, because 530450230333 - 217 = 530450099261 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 530450230295 and 530450230304.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (530450230313) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265225115166 + 265225115167.

It is an arithmetic number, because the mean of its divisors is an integer number (265225115167).

Almost surely, 2530450230333 is an apocalyptic number.

It is an amenable number.

530450230333 is a deficient number, since it is larger than the sum of its proper divisors (1).

530450230333 is an equidigital number, since it uses as much as digits as its factorization.

530450230333 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48600, while the sum is 31.

Adding to 530450230333 its reverse (333032054035), we get a palindrome (863482284368).

The spelling of 530450230333 in words is "five hundred thirty billion, four hundred fifty million, two hundred thirty thousand, three hundred thirty-three".