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5304535444441 is a prime number
BaseRepresentation
bin100110100110000111011…
…1100110110101111011001
3200210002221012021121022001
41031030032330312233121
51143402142033210231
615140511524001001
71055145222220552
oct115141674665731
920702835247261
105304535444441
111765705a73352
1271807a230161
132c62a57297bc
14144a52dbd329
1592eb3170b61
hex4d30ef36bd9

5304535444441 has 2 divisors, whose sum is σ = 5304535444442. Its totient is φ = 5304535444440.

The previous prime is 5304535444391. The next prime is 5304535444493. The reversal of 5304535444441 is 1444445354035.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3376314375625 + 1928221068816 = 1837475^2 + 1388604^2 .

It is a cyclic number.

It is not a de Polignac number, because 5304535444441 - 215 = 5304535411673 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 5304535444391 and 5304535444400.

It is not a weakly prime, because it can be changed into another prime (5304535441441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2652267722220 + 2652267722221.

It is an arithmetic number, because the mean of its divisors is an integer number (2652267722221).

Almost surely, 25304535444441 is an apocalyptic number.

It is an amenable number.

5304535444441 is a deficient number, since it is larger than the sum of its proper divisors (1).

5304535444441 is an equidigital number, since it uses as much as digits as its factorization.

5304535444441 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4608000, while the sum is 46.

The spelling of 5304535444441 in words is "five trillion, three hundred four billion, five hundred thirty-five million, four hundred forty-four thousand, four hundred forty-one".