Base | Representation |
---|---|
bin | 110001011001110100… |
… | …100000011111010101 |
3 | 12001220220102122210110 |
4 | 301121310200133111 |
5 | 1332114403404331 |
6 | 40211431313233 |
7 | 3555354121140 |
oct | 613164403725 |
9 | 161826378713 |
10 | 53046544341 |
11 | 2055143399a |
12 | a34521b819 |
13 | 5004c9c79b |
14 | 27d31b1057 |
15 | 15a707e946 |
hex | c59d207d5 |
53046544341 has 32 divisors (see below), whose sum is σ = 82193810688. Its totient is φ = 29802378240.
The previous prime is 53046544267. The next prime is 53046544349. The reversal of 53046544341 is 14344564035.
53046544341 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 53046544341 - 29 = 53046543829 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 53046544341.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53046544349) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 3442045 + ... + 3457421.
It is an arithmetic number, because the mean of its divisors is an integer number (2568556584).
Almost surely, 253046544341 is an apocalyptic number.
It is an amenable number.
53046544341 is a deficient number, since it is larger than the sum of its proper divisors (29147266347).
53046544341 is a wasteful number, since it uses less digits than its factorization.
53046544341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 18141.
The product of its (nonzero) digits is 345600, while the sum is 39.
The spelling of 53046544341 in words is "fifty-three billion, forty-six million, five hundred forty-four thousand, three hundred forty-one".
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