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53047703 is a prime number
BaseRepresentation
bin1100101001011…
…1000110010111
310200211002202202
43022113012113
5102040011303
65132555115
71212620012
oct312270627
9120732682
1053047703
1127a42585
1215922a9b
13acb4697
14708c379
1549ccc88
hex3297197

53047703 has 2 divisors, whose sum is σ = 53047704. Its totient is φ = 53047702.

The previous prime is 53047691. The next prime is 53047733. The reversal of 53047703 is 30774035.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-53047703 is a prime.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (53047733) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26523851 + 26523852.

It is an arithmetic number, because the mean of its divisors is an integer number (26523852).

Almost surely, 253047703 is an apocalyptic number.

53047703 is a deficient number, since it is larger than the sum of its proper divisors (1).

53047703 is an equidigital number, since it uses as much as digits as its factorization.

53047703 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8820, while the sum is 29.

The square root of 53047703 is about 7283.3854078993. The cubic root of 53047703 is about 375.7412372881.

The spelling of 53047703 in words is "fifty-three million, forty-seven thousand, seven hundred three".