Base | Representation |
---|---|
bin | 100110100110010110000… |
… | …0010010010111111010011 |
3 | 200210011012012110211101101 |
4 | 1031030230002102333103 |
5 | 1143404141443111011 |
6 | 15141032154445231 |
7 | 1055163265653214 |
oct | 115145402227723 |
9 | 20704165424341 |
10 | 5305023410131 |
11 | 1765936460185 |
12 | 718195733817 |
13 | 2c635285a0b3 |
14 | 144a9bb2140b |
15 | 92ee0e0d2c1 |
hex | 4d32c092fd3 |
5305023410131 has 2 divisors, whose sum is σ = 5305023410132. Its totient is φ = 5305023410130.
The previous prime is 5305023410059. The next prime is 5305023410147. The reversal of 5305023410131 is 1310143205035.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5305023410131 - 213 = 5305023401939 is a prime.
It is a super-2 number, since 2×53050234101312 (a number of 26 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 5305023410131.
It is not a weakly prime, because it can be changed into another prime (5305023410231) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2652511705065 + 2652511705066.
It is an arithmetic number, because the mean of its divisors is an integer number (2652511705066).
Almost surely, 25305023410131 is an apocalyptic number.
5305023410131 is a deficient number, since it is larger than the sum of its proper divisors (1).
5305023410131 is an equidigital number, since it uses as much as digits as its factorization.
5305023410131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5400, while the sum is 28.
Adding to 5305023410131 its reverse (1310143205035), we get a palindrome (6615166615166).
The spelling of 5305023410131 in words is "five trillion, three hundred five billion, twenty-three million, four hundred ten thousand, one hundred thirty-one".
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