Base | Representation |
---|---|
bin | 1111011100001010000… |
… | …11000001111011000001 |
3 | 1212201100101001220100012 |
4 | 13232011003001323001 |
5 | 32142442331011231 |
6 | 1043414145434305 |
7 | 53220416204363 |
oct | 7560503017301 |
9 | 1781311056305 |
10 | 530513141441 |
11 | 194a97924268 |
12 | 8699793b995 |
13 | 3b04791965a |
14 | 1b969884d33 |
15 | dbee81de2b |
hex | 7b850c1ec1 |
530513141441 has 2 divisors, whose sum is σ = 530513141442. Its totient is φ = 530513141440.
The previous prime is 530513141413. The next prime is 530513141471. The reversal of 530513141441 is 144141315035.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 324306331441 + 206206810000 = 569479^2 + 454100^2 .
It is a cyclic number.
It is not a de Polignac number, because 530513141441 - 230 = 529439399617 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 530513141398 and 530513141407.
It is not a weakly prime, because it can be changed into another prime (530513141471) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265256570720 + 265256570721.
It is an arithmetic number, because the mean of its divisors is an integer number (265256570721).
Almost surely, 2530513141441 is an apocalyptic number.
It is an amenable number.
530513141441 is a deficient number, since it is larger than the sum of its proper divisors (1).
530513141441 is an equidigital number, since it uses as much as digits as its factorization.
530513141441 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14400, while the sum is 32.
Adding to 530513141441 its reverse (144141315035), we get a palindrome (674654456476).
The spelling of 530513141441 in words is "five hundred thirty billion, five hundred thirteen million, one hundred forty-one thousand, four hundred forty-one".
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