Base | Representation |
---|---|
bin | 110001011010001101… |
… | …101001010011011100 |
3 | 12001221100211110011112 |
4 | 301122031221103130 |
5 | 1332123100242134 |
6 | 40212224441152 |
7 | 3555464125121 |
oct | 613215512334 |
9 | 161840743145 |
10 | 53053134044 |
11 | 20555124929 |
12 | a3474791b8 |
13 | 5006469011 |
14 | 27d4008748 |
15 | 15a79321ce |
hex | c5a3694dc |
53053134044 has 12 divisors (see below), whose sum is σ = 92900341800. Its totient is φ = 26510179248.
The previous prime is 53053134041. The next prime is 53053134067. The reversal of 53053134044 is 44043135035.
53053134044 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a self number, because there is not a number n which added to its sum of digits gives 53053134044.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53053134041) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4089659 + ... + 4102610.
It is an arithmetic number, because the mean of its divisors is an integer number (7741695150).
Almost surely, 253053134044 is an apocalyptic number.
It is an amenable number.
53053134044 is a deficient number, since it is larger than the sum of its proper divisors (39847207756).
53053134044 is a wasteful number, since it uses less digits than its factorization.
53053134044 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8193892 (or 8193890 counting only the distinct ones).
The product of its (nonzero) digits is 43200, while the sum is 32.
Adding to 53053134044 its reverse (44043135035), we get a palindrome (97096269079).
Subtracting from 53053134044 its reverse (44043135035), we obtain a palindrome (9009999009).
The spelling of 53053134044 in words is "fifty-three billion, fifty-three million, one hundred thirty-four thousand, forty-four".
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