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53053134044 = 2216198192269
BaseRepresentation
bin110001011010001101…
…101001010011011100
312001221100211110011112
4301122031221103130
51332123100242134
640212224441152
73555464125121
oct613215512334
9161840743145
1053053134044
1120555124929
12a3474791b8
135006469011
1427d4008748
1515a79321ce
hexc5a3694dc

53053134044 has 12 divisors (see below), whose sum is σ = 92900341800. Its totient is φ = 26510179248.

The previous prime is 53053134041. The next prime is 53053134067. The reversal of 53053134044 is 44043135035.

53053134044 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a self number, because there is not a number n which added to its sum of digits gives 53053134044.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (53053134041) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4089659 + ... + 4102610.

It is an arithmetic number, because the mean of its divisors is an integer number (7741695150).

Almost surely, 253053134044 is an apocalyptic number.

It is an amenable number.

53053134044 is a deficient number, since it is larger than the sum of its proper divisors (39847207756).

53053134044 is a wasteful number, since it uses less digits than its factorization.

53053134044 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8193892 (or 8193890 counting only the distinct ones).

The product of its (nonzero) digits is 43200, while the sum is 32.

Adding to 53053134044 its reverse (44043135035), we get a palindrome (97096269079).

Subtracting from 53053134044 its reverse (44043135035), we obtain a palindrome (9009999009).

The spelling of 53053134044 in words is "fifty-three billion, fifty-three million, one hundred thirty-four thousand, forty-four".

Divisors: 1 2 4 1619 3238 6476 8192269 16384538 32769076 13263283511 26526567022 53053134044